A point moves in xy plane such that sum of its distance from two mutually perpendicular lines is always 3.The area encloded by the locus of the point is


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Question Number 31371 by momo last updated on 07/Mar/18

$A p o i n t m o v e s i n x y p l a n e s u c h$ $t h a t s u m o f i t s d i s t a n c e f r o m t w o$ $m u t u a l l y p e r p e n d i c u l a r l i n e s i s$ $a l w a y s 3 . T h e a r e a e n c l o d e d b y$ $t h e l o c u s o f t h e p o i n t i s$
	Answered by ajfour last updated on 07/Mar/18

	$A r e a e n c l o s e d b y$ $∣ x ∣ + ∣ y ∣= 3 i s = {(3 \sqrt{2})}^{2} = 18 s q . u n i t s .$
	Commented by momo last updated on 07/Mar/18

	$e x p l a i n p l e a s e$
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