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Question Number 31423 by mondodotto@gmail.com last updated on 08/Mar/18

Commented by mondodotto@gmail.com last updated on 08/Mar/18

$please help me!$
	Answered by MJS last updated on 08/Mar/18

	$x^{4} + 6 x^{3} + 13 x^{2} + p x + q$ ${(x^{2} + m x + n)}^{2} =$ $= x^{4} + 2 {m x}^{3} + (m^{2} + 2 n) x^{2} + 2 m n x + n^{2}$ $2 m = 6 \Rightarrow m = 3$ $m^{2} + 2 n = 13 \Rightarrow n = 2$ $2 m n = p \Rightarrow p = 12$ $n^{2} = q \Rightarrow q = 4$ $\Rightarrow p - 2 q = 4$ $x^{4} + 6 x^{3} + 13 x^{2} + 12 x + 4 =$ $= {(x^{2} + 3 x + 2)}^{2}$
	Commented by mondodotto@gmail.com last updated on 08/Mar/18

	$what do m and n means ?$
	Commented by rahul 19 last updated on 08/Mar/18

	$f o r t h e s a k e o f s o l v i n g t h e y a r e j u s t$ $t a k e n a s t h e i n t e g r a l c o e f f i c i e n t s .$
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