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Question Number 31543 by Cheyboy last updated on 09/Mar/18
∫x3+x+1x2+1dx
Commented by prof Abdo imad last updated on 10/Mar/18
I=∫x(x2+1)+1x2+1dx=∫xdx+∫dxx2+1=x22+arctanx+λ.
Commented by Cheyboy last updated on 10/Mar/18
Thankyousir
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