Question Number 31626 by Tinkutara last updated on 11/Mar/18
Answered by Joel578 last updated on 11/Mar/18
$$\left(\mathrm{1}\right) \\ $$$$\mathrm{2Cu}\:+\:\mathrm{6HNO}_{\mathrm{3}} \:\rightarrow\:\mathrm{2Cu}\left(\mathrm{NO}_{\mathrm{3}} \right)_{\mathrm{2}} \:+\:\mathrm{NO}\:+\:\mathrm{NO}_{\mathrm{2}} \:+\:\mathrm{3H}_{\mathrm{2}} \mathrm{O} \\ $$
Commented by Tinkutara last updated on 11/Mar/18
Yes I too balanced and got (1). But answer given is 2⃣. That probably came by multiplying the whole equation by 2.
Commented by Joel578 last updated on 11/Mar/18
$$\mathrm{if}\:\mathrm{the}\:\mathrm{answer}\:\mathrm{is}\:\left(\mathrm{2}\right),\:\mathrm{the}\:\mathrm{reaction}\:\mathrm{would}\:\mathrm{be} \\ $$$$\mathrm{4Cu}\:+\:\mathrm{12HNO}_{\mathrm{3}} \:\rightarrow\:\mathrm{4Cu}\left(\mathrm{NO}_{\mathrm{3}} \right)_{\mathrm{2}} \:+\:\mathrm{2NO}\:+\:\mathrm{2NO}_{\mathrm{2}} \:+\:\mathrm{6H}_{\mathrm{2}} \mathrm{O} \\ $$$$\mathrm{it}\:\mathrm{can}\:\mathrm{be}\:\mathrm{simplified}\:\mathrm{into}\:\left(\mathrm{1}\right) \\ $$
Commented by Joel578 last updated on 12/Mar/18
$$\left(\mathrm{1}\right)\:\mathrm{is}\:\mathrm{the}\:\mathrm{correct}\:\mathrm{answer}\:\mathrm{I}\:\mathrm{think} \\ $$
Commented by Tinkutara last updated on 12/Mar/18
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