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Question Number 31669 by gunawan last updated on 12/Mar/18

A={(m/n)+((8n)/m) : m, n ∈ N} N= natural numbers  supremum ?  infimum?

$$\mathrm{A}=\left\{\frac{{m}}{{n}}+\frac{\mathrm{8}{n}}{{m}}\::\:{m},\:{n}\:\in\:\mathrm{N}\right\}\:\mathrm{N}=\:\mathrm{natural}\:\mathrm{numbers} \\ $$$$\mathrm{supremum}\:? \\ $$$$\mathrm{infimum}? \\ $$

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