Calculate the moment of inertia of the earth abouth its axis.If the mass of the earth is 6.0×10^(34) kg and radius 6.4×10^6 m. (Assume the earth to be a perfect sphere)


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Question Number 31766 by NECx last updated on 14/Mar/18

$C a l c u l a t e t h e m o m e n t o f i n e r t i a$ $o f t h e e a r t h a b o u t h i t s a x i s . I f$ $t h e m a s s o f t h e e a r t h i s 6.0 \times 10^{34} k g$ $a n d r a d i u s 6.4 \times 10^{6} m .$ $(A s s u m e t h e e a r t h t o b e a p e r f e c t$ $s p h e r e)$
Commented by Tinkutara last updated on 14/Mar/18

$\frac{2}{5} {M R}^{2} = 9.8304 \times 10^{47} k g m^{2}$
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