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Question Number 31785 by yesasitya22@gmail.com last updated on 14/Mar/18

$$A=\left[\begin{array}{c}15\\ 67\end{array}\right]find{A}^k$$

Answered by kaivan.ahmadi last updated on 16/Dec/18

$$\mathrm{sice}\mathrm{A}\mathrm{is}2\times 1\mathrm{so}\mathrm{we}\mathrm{cant}\mathrm{calcute}{\mathrm{A}}^2$$$$\mathrm{also}{\mathrm{A}}^{\mathrm{k}}$$

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