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Question Number 31868 by 6123 last updated on 16/Mar/18

Let a>b>1 be positive integers with b odd.  Let n be a positive integer as well. If  b^n  divides  a^n −1, prove that a^b  > (3^n /n).  Solution please. Thanks in advance!!

$${Let}\:{a}>{b}>\mathrm{1}\:{be}\:{positive}\:{integers}\:{with}\:{b}\:{odd}. \\ $$ $${Let}\:{n}\:{be}\:{a}\:{positive}\:{integer}\:{as}\:{well}.\:{If}\:\:{b}^{{n}} \:{divides} \\ $$ $${a}^{{n}} −\mathrm{1},\:{prove}\:{that}\:{a}^{{b}} \:>\:\frac{\mathrm{3}^{{n}} }{{n}}. \\ $$ $${Solution}\:{please}.\:{Thanks}\:{in}\:{advance}!! \\ $$

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