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Question Number 32002 by rahul 19 last updated on 18/Mar/18
Ifz3=z¯provethen∣z∣=1.
Answered by Tinkutara last updated on 18/Mar/18
z3=z¯∣z3∣=∣z¯∣∣z∣3=∣z∣∣z∣2=1∣z∣=1
Commented by Tinkutara last updated on 18/Mar/18
∣z∣isalways⩾0.Ifz=x+iythen∣z∣=x2+y2,wherebothx,y∈Randsquarerootofrealnumberistakenasrealnumberonly.
Commented by rahul 19 last updated on 18/Mar/18
thanku!
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