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Question Number 32026 by abdo imad last updated on 18/Mar/18
letα>0provethat∑n=0∞(−1)nn+α=∫01xα−11+xdx.
Commented byabdo imad last updated on 22/Mar/18
∫01xα−11+xdx=∫01(∑n=0∞(−1)nxn)xα−1dx =∑n=0∞(−1)n∫01xn+α−1dx =∑n=0∞(−1)n[1n+αxn+α]01=∑n=0∞(−1)nn+α.
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