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Question Number 32126 by mondodotto@gmail.com last updated on 20/Mar/18

Commented by mondodotto@gmail.com last updated on 20/Mar/18

please help

pleasehelp

Answered by mrW2 last updated on 20/Mar/18

∫((ln x −1)/((ln x)^2 )) dx  =∫(1/(ln x)) dx−∫(1/((ln x)^2 )) dx  =(x/(ln x))+∫(x/(x(ln x)^2 )) dx−∫(1/((ln x)^2 )) dx  =(x/(ln x))+C

lnx1(lnx)2dx=1lnxdx1(lnx)2dx=xlnx+xx(lnx)2dx1(lnx)2dx=xlnx+C

Commented by mondodotto@gmail.com last updated on 20/Mar/18

thanx a lot

thanxalot

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