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Question Number 32137 by Joel578 last updated on 20/Mar/18

$$\underset{x\to 5}{\lim }\frac{f\left(x\right)g\left(x\right)-3g\left(x\right)-3}{f\left(x\right)-3(x-5)}=0$$$$\mathrm{Find}\mathrm{the}\mathrm{value}\mathrm{of}{g}^{\prime }\left(5\right)$$

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