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Question Number 32241 by mondodotto@gmail.com last updated on 22/Mar/18

Commented by MJS last updated on 22/Mar/18

I don′t think that′s true if you  can freely choose a, b and θ  but of course you can find θ  for any given triplet a, b, c  with  or without a^2 +b^2 =c^2

$$\mathrm{I}\:\mathrm{don}'\mathrm{t}\:\mathrm{think}\:\mathrm{that}'\mathrm{s}\:\mathrm{true}\:\mathrm{if}\:\mathrm{you} \\ $$$$\mathrm{can}\:\mathrm{freely}\:\mathrm{choose}\:{a},\:{b}\:\mathrm{and}\:\theta \\ $$$$\mathrm{but}\:\mathrm{of}\:\mathrm{course}\:\mathrm{you}\:\mathrm{can}\:\mathrm{find}\:\theta \\ $$$$\mathrm{for}\:\mathrm{any}\:\mathrm{given}\:\mathrm{triplet}\:{a},\:{b},\:{c}\:\:\mathrm{with} \\ $$$$\mathrm{or}\:\mathrm{without}\:{a}^{\mathrm{2}} +{b}^{\mathrm{2}} ={c}^{\mathrm{2}} \\ $$

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