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Question Number 32329 by naeems1000 last updated on 23/Mar/18

The smallest number which must be  subtracted from 3400 to make it a   perfect cube is _____.

$$\mathrm{The}\:\mathrm{smallest}\:\mathrm{number}\:\mathrm{which}\:\mathrm{must}\:\mathrm{be} \\ $$$$\mathrm{subtracted}\:\mathrm{from}\:\mathrm{3400}\:\mathrm{to}\:\mathrm{make}\:\mathrm{it}\:\mathrm{a}\: \\ $$$$\mathrm{perfect}\:\mathrm{cube}\:\mathrm{is}\:\_\_\_\_\_. \\ $$

Answered by Joel578 last updated on 23/Mar/18

15^3  = 3375  3400 − 3375 = 25

$$\mathrm{15}^{\mathrm{3}} \:=\:\mathrm{3375} \\ $$$$\mathrm{3400}\:−\:\mathrm{3375}\:=\:\mathrm{25} \\ $$

Answered by mrW2 last updated on 23/Mar/18

^3 (√(3400))=15.04  ⇒3400−15^3 =25

$$\:^{\mathrm{3}} \sqrt{\mathrm{3400}}=\mathrm{15}.\mathrm{04} \\ $$$$\Rightarrow\mathrm{3400}−\mathrm{15}^{\mathrm{3}} =\mathrm{25} \\ $$

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