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Question Number 32364 by prof Abdo imad last updated on 23/Mar/18
letun=(e−(1+1n)n)n2+2−n2+1findlimun
Commented by prof Abdo imad last updated on 06/Apr/18
wehaveAn=n2+2−n2+1=n(1+2n−1+1n)but1+2n∼1+1nand1+1n∼1+12n⇒An∼n+1−n−12⇒An∼12alsowehave(1+1n)n=enln(1+1n)ln(1+x))′=11+x=1−x+o(x2)forx∈V(o)ln(1+x)=x−x22+o(x3)⇒ln(1+1n)=1n−12n2+o(1n3)⇒nln(1+1n)=1−12n+o(1n2)⇒enln(1+1n)=e1−12n+o(1n2)=e.(1−12n+o(1n2))⇒e−(1+1n)n∼e2n+o(1n2)⇒un∼e2n⇒limn→∞un=0.
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