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Question Number 32396 by saru53424@gmail.com last updated on 24/Mar/18

roots  2x×x+x+3

roots2x×x+x+3

Answered by $@ty@m last updated on 24/Mar/18

2x^2 +x+3=0  a=2 b=1 c=3  D=b^2 −4ac=−23  x=((−b±(√D))/(2a))  =((−1±(√(−23)))/4)  =((−1)/4)±((√(23))/4)i

2x2+x+3=0a=2b=1c=3D=b24ac=23x=b±D2a=1±234=14±234i

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