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Question Number 32402 by saru53424@gmail.com last updated on 24/Mar/18
∫x+21−x
Commented by abdo imad last updated on 24/Mar/18
∫x+21−xdx=−∫x+2x−1dx=−∫x−1+3x−1dx=−x−3∫dxx−1=−x−3ln∣x−1∣+λ.
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