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Question Number 32409 by saru53424@gmail.com last updated on 24/Mar/18

Answered by rahul 19 last updated on 24/Mar/18

option 2−3. x^3 −4x^2 −x+4= (x−1)(x^2 −3x−4) ⇒ L_(x→4) t_ = x−1 ⇒4−1=3★

option2−3.x3−4x2−x+4=(x−1)(x2−3x−4)⇒Lx→4t=x−1⇒4−1=3★

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