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Question Number 32535 by naka3546 last updated on 27/Mar/18

k  ≤  2018  f (f (n) )  =  2n  f (k)  =  2018  how  many   the possible of   k  integers ?

$${k}\:\:\leqslant\:\:\mathrm{2018} \\ $$$${f}\:\left({f}\:\left({n}\right)\:\right)\:\:=\:\:\mathrm{2}{n} \\ $$$${f}\:\left({k}\right)\:\:=\:\:\mathrm{2018} \\ $$$${how}\:\:{many}\:\:\:{the}\:{possible}\:{of}\:\:\:\boldsymbol{{k}}\:\:{integers}\:? \\ $$

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