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Question Number 32635 by mondodotto@gmail.com last updated on 29/Mar/18

Commented by Joel578 last updated on 30/Mar/18

$$\mathrm{Use}\mathrm{substitution}$$$$u=e^{e^{{\text{iddots}}^x}}\left(8e\mathrm{as}\mathrm{powers}\right)$$$$\mathrm{and}\mathrm{gives}\mathrm{you}$$$$I=\int e^{u}du$$

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