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Question Number 32640 by Rio Mike last updated on 30/Mar/18
Giventhefunctionf:x→x+13xandg:x→x−1.Finda)fgb)f°gc)gf−1(x)
Answered by Joel578 last updated on 30/Mar/18
f(x)=x+13x,g(x)=x−1(f∘g)(x)=f(x−1)=(x−1)+13(x−1)=x3x−3(g∘f)(x)=g(x+13x)=x+13x−3x3x=1−2x3xf−1(x)=13x−1(g∘f−1)(x)=g(13x−1)=13x−1−3x−13x−1=2−3x3x−1
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