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Question Number 32891 by mondodotto@gmail.com last updated on 05/Apr/18

Commented by Tinkutara last updated on 05/Apr/18

It is wrong.

Commented by Joel578 last updated on 05/Apr/18

$$\sec x=\frac{1}{\cos x}$$

Commented by mrW2 last updated on 06/Apr/18

$${\sec }^{-1}x\ne {\left(\sec x\right)}^{-1}$$$${\sec }^{-1}x=arcsecx$$$${\left(secx\right)}^{-1}=\frac{1}{\sec x}=\cos x$$

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