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Question Number 32954 by mondodotto@gmail.com last updated on 07/Apr/18

 log_2 x×log_4 x×log_(16) x=7   help

log2x×log4x×log16x=7help

Answered by MJS last updated on 08/Apr/18

log_2  x×(1/2)log_2  x×(1/4)log_2  x=7  (1/8)(log_2  x)^3 =7  log_2  x=2(7)^(1/3)   x=2^(2(7)^(1/3) ) =4^(7)^(1/3)  ≈14.18075

log2x×12log2x×14log2x=718(log2x)3=7log2x=273x=2273=47314.18075

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