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Question Number 33152 by Rio Mike last updated on 11/Apr/18
itisgiventhat1n∑nr=1xr=2and1n∑nr=1(xr)2−1n2(∑nr=1)2=3determineintermsofnthevalueof.∑nr=1(xr+1)2
Commented by prof Abdo imad last updated on 12/Apr/18
wehave∑r=1nxr=2n,1n∑r=1nxr2−1=9because(Σ1)2=n2⇒∑r=1nxr2=10nso∑r=1n(xr+1)2=∑r=1n(xr2+2xr+1)=∑r=1nxr2+2∑r=1nxr+n=10n+4n+n=15n(ifthereisnomistakeinthequestion)
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