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Question Number 33239 by Tinkutara last updated on 13/Apr/18

Answered by ajfour last updated on 14/Apr/18

$$2\left[mu\cos \left(\frac{\alpha }{2}\right)\right]=\left(2m\right)\left(\frac{u}{2}\right)$$$$\Rightarrow \cos \left(\frac{\alpha }{2}\right)=\frac{1}{2}\Rightarrow \alpha =120°.$$

Commented by Tinkutara last updated on 15/Apr/18

But why after collision particles will stick together? Because components of velocities normal to Line of Impact will remain unchanged.

Commented by ajfour last updated on 15/Apr/18

$$afterperfectlyinelasticcollision$$$$particlessticktogether.$$$$e=0\Rightarrow \frac{v_{separation}}{v_{approach}}=0$$$$\Rightarrow v_{separation}=v_1-v_2=0.$$

Commented by Tinkutara last updated on 15/Apr/18

But isn't that only in 1D and not in 2D?

Commented by ajfour last updated on 15/Apr/18

$$in3Daswell.$$

Commented by Tinkutara last updated on 15/Apr/18

Thank you very much Sir! I got the answer. ��������

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