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Question Number 33363 by soufiane zarik last updated on 15/Apr/18

Commented by soufiane zarik last updated on 15/Apr/18

thank you sir !!

$$\mathrm{thank}\:\mathrm{you}\:\mathrm{sir}\:!! \\ $$

Commented by Rasheed.Sindhi last updated on 15/Apr/18

If   m,n∈Z  (√m)+(√n)=2(√3)  (√m)+(√n)=(√3)+(√3)  m=n=3  m^2 +n^2 =3^2 +3^2 =18

$$\mathrm{If}\:\:\:\mathrm{m},\mathrm{n}\in\mathbb{Z} \\ $$$$\sqrt{\mathrm{m}}+\sqrt{\mathrm{n}}=\mathrm{2}\sqrt{\mathrm{3}} \\ $$$$\sqrt{\mathrm{m}}+\sqrt{\mathrm{n}}=\sqrt{\mathrm{3}}+\sqrt{\mathrm{3}} \\ $$$$\mathrm{m}=\mathrm{n}=\mathrm{3} \\ $$$$\mathrm{m}^{\mathrm{2}} +\mathrm{n}^{\mathrm{2}} =\mathrm{3}^{\mathrm{2}} +\mathrm{3}^{\mathrm{2}} =\mathrm{18} \\ $$

Commented by MJS last updated on 15/Apr/18

m, n∈Z  m=0 ⇒ n=12 ⇒ m^2 +n^2 =144

$${m},\:{n}\in\mathbb{Z} \\ $$$${m}=\mathrm{0}\:\Rightarrow\:{n}=\mathrm{12}\:\Rightarrow\:{m}^{\mathrm{2}} +{n}^{\mathrm{2}} =\mathrm{144} \\ $$

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