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Question Number 33413 by Rio Mike last updated on 15/Apr/18
thevalueofθ,intherange0°⩽θ⩽90°forwhichsinθ=cosθis...?
Commented by Rasheed.Sindhi last updated on 16/Apr/18
sinθ=cos(90−θ)θ=90−θ2θ=90θ=45sin45=cos45
Commented by abdo imad last updated on 17/Apr/18
sinθ=cosθ⇔sinθ=sin(π2−θ)⇔θ=π2−θ+2kπorθ=π−(π2−θ)+2kπ(k∈Z)⇔2θ=π2+2kπorθ=π2+θ+2kπ⇔θ=π4+kπbutwehave0⩽θ⩽π2⇒0⩽π4+kπ⩽π2⇒0⩽14+k⩽12⇒−14⩽k⩽14⇒k=0⇒θ=π4.
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