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Question Number 33463 by NECx last updated on 17/Apr/18
Findthepricipalandordinaryargumentofz=i−2−2i
Commented by abdo imad last updated on 17/Apr/18
z=−i2(1+i)=−i(1−i)4=1−i4⇒∣z∣=14∣1−i∣=24z=14−i4=24(12−i2)=22e−iπ4⇒arg(z)≡−π4[2π].
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