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Question Number 33494 by mondodotto@gmail.com last updated on 17/Apr/18

 ∫(e^x /(sin^2 x    ))dx

exsin2xdx

Commented by math khazana by abdo last updated on 18/Apr/18

∫    (e^x /(sin^2 x))dx = ∫  (e^x /((1−cos(2x))/2))dx  = 2 ∫     (e^x /(1−cos(2x)))dx  =_(2x=t)   2 ∫      (e^(t/2) /(1−cost)) (dt/2)

exsin2xdx=ex1cos(2x)2dx=2ex1cos(2x)dx=2x=t2et21costdt2

Commented by math khazana by abdo last updated on 18/Apr/18

∫  (e^x /(sin^2 x))dx  = ∫  e^(t/2)   (Σ_(n=0) ^∞  cos^n t)dt  = Σ_(n=0) ^∞    ∫   e^(t/2)   cos^n t dt  = Σ_(n=0) ^∞   A_n    with  A_n  = ∫  e^(t/2)  cos^n t dt  integral calculable by recurence

exsin2xdx=et2(n=0cosnt)dt=n=0et2cosntdt=n=0AnwithAn=et2cosntdtintegralcalculablebyrecurence

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