Question and Answers Forum

All Questions      Topic List

None Questions

Previous in All Question      Next in All Question      

Previous in None      Next in None      

Question Number 33644 by mondodotto@gmail.com last updated on 21/Apr/18

$$\int \left({\mathbf{sec}}^2\mathit{x}\right){\mathit{e}}^{\mathbf{tan}\mathit{x}}\mathit{d}\mathit{x}$$

Answered by Joel578 last updated on 21/Apr/18

$$I=\int \left({\sec }^{2}x\right)e^{\tan x}dx$$$$u=\tan x\to du={\sec }^{2}xdx$$$$$$$$I=\int e^{u}du$$$$=e^u+C=e^{\tan x}+C$$

Terms of Service

Privacy Policy

Contact: info@tinkutara.com