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Question Number 34081 by Aditya 879 last updated on 30/Apr/18

2^n −2^(n−1) =4 .find n^(n.)

2n−2n−1=4.findnn.

Answered by math1967 last updated on 30/Apr/18

2^n (1−2^(−1) )=4 2^n (1−(1/2))=4 2^n ×(1/2)=4 2^n =8∴2^n =2^3 ∴n=3 ∴n^n =3^3 =27

2n(1−2−1)=42n(1−12)=42n×12=42n=8∴2n=23∴n=3∴nn=33=27

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