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Question Number 34182 by NECx last updated on 02/May/18
resolvex3x6−1intopartialfraction
Answered by math1967 last updated on 02/May/18
12{1x3+1+1x3−1}
Answered by MJS last updated on 02/May/18
x6−1=(x−1)(x+1)(x2−x+1)(x2+x+1)x3x6−1=16(1x−1+1x+1−x−2x2−x+1−x+2x2+x+1)
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