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Question Number 34357 by math1967 last updated on 05/May/18
Ifa+b+c=0provethati)(ab+c+bc+a+ca+b)(b+ca+c+ab+a+bc)=9ii)(ab−c+bc−a+ca−b)(b−ca+c−ab+a−bc)=9
Answered by tanmay.chaudhury50@gmail.com last updated on 05/May/18
i){(ab+c+1−1)+(bc+a+1−1)+(ca+b+1−1)}×{(b+ca+1−1)+(c+ab+1−1)+(a+bc+1−1)}={(a+b+cb+c−1)+(a+b+cc+a−1)+(a+b+ca+b−1)}×{(a+b+ca−1)+(a+b+cb−1)+(a+b+cc−1)}=givena+b+c=0so=(−3)×(−3)=9
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