Question and Answers Forum

All Questions      Topic List

Trigonometry Questions

Previous in All Question      Next in All Question      

Previous in Trigonometry      Next in Trigonometry      

Question Number 34420 by math khazana by abdo last updated on 06/May/18

let A  = arctanx −arctany  give another form of A if  xy≠−1 .

$${let}\:{A}\:\:=\:{arctanx}\:−{arctany} \\ $$$${give}\:{another}\:{form}\:{of}\:{A}\:{if}\:\:{xy}\neq−\mathrm{1}\:. \\ $$

Commented by math khazana by abdo last updated on 07/May/18

we have tanA =tan(arctanx−arctany)  = ((x−y)/(1+xy))  ⇒ A= arctan( ((x−y)/(1+xy)))

$${we}\:{have}\:{tanA}\:={tan}\left({arctanx}−{arctany}\right) \\ $$$$=\:\frac{{x}−{y}}{\mathrm{1}+{xy}}\:\:\Rightarrow\:{A}=\:{arctan}\left(\:\frac{{x}−{y}}{\mathrm{1}+{xy}}\right) \\ $$

Answered by tanmay.chaudhury50@gmail.com last updated on 07/May/18

A=tan^(−1) x−tan^(−1) y  =tan^(−1) (((x−y)/(1+xy)))

$${A}={tan}^{−\mathrm{1}} {x}−{tan}^{−\mathrm{1}} {y} \\ $$$$={tan}^{−\mathrm{1}} \left(\frac{{x}−{y}}{\mathrm{1}+{xy}}\right) \\ $$

Terms of Service

Privacy Policy

Contact: info@tinkutara.com