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Question Number 34617 by ajfour last updated on 09/May/18

Commented by candre last updated on 09/May/18

$r_{t h} = R_{1} ∥ R_{3} + R_{2} ∥ R_{4}$ $V_{t h} = (\frac{R_{3}}{R_{1} + R_{3}} - \frac{R_{4}}{R_{2} + R_{4}}) ε$ $I = \frac{V_{t h}}{r_{t h}}$
Commented by ajfour last updated on 09/May/18

$F i n d c u r r e n t I .$
	Answered by ajfour last updated on 09/May/18

	$I = i_{1} - i_{3}$ $i = \frac{ε}{(\frac{R_{1} R_{2}}{R_{1} + R_{2}} + \frac{R_{3} R_{4}}{R_{3} + R_{4}})}$ $i_{1} = i (\frac{R_{2}}{R_{1} + R_{2}}); i_{3} = i (\frac{R_{4}}{R_{3} + R_{4}})$ $I = \frac{ε}{(\frac{R_{1} R_{2}}{R_{1} + R_{2}} + \frac{R_{3} R_{4}}{R_{3} + R_{4}})} [\frac{R_{2}}{R_{1} + R_{2}} - \frac{R_{4}}{R_{3} + R_{4}}]$ $I = \frac{ε (R_{2} R_{3} - R_{1} R_{4})}{R_{1} R_{2} (R_{3} + R_{4}) + R_{3} R_{4} (R_{1} + R_{2})} .$
	Answered by tanmay.chaudhury50@gmail.com last updated on 09/May/18

	$f o r b a l a n c e d w h e a s t o n b r i d g e t h a t m e a n s$ $w h e n \frac{R_{1}}{R_{2}} = \frac{R_{3}}{R_{4_{}}} I = 0$
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