A man pushes a box of 40kg up an incline of 15°,if the man applies a horizontal force 200N and the box moves up the plane a distance of 20m at a constant velocity and the coefficient of friction is 0.1, find a)the workdone by the man on the box b)workdone against friction


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Question Number 34703 by NECx last updated on 10/May/18

$A m a n p u s h e s a b o x o f 40 k g u p a n$ $i n c l i n e o f 15 °, i f t h e m a n a p p l i e s$ $a h o r i z o n t a l f o r c e 200 N a n d t h e$ $b o x m o v e s u p t h e p l a n e a d i s t a n c e$ $o f 20 m a t a c o n s t a n t v e l o c i t y a n d$ $t h e c o e f f i c i e n t o f f r i c t i o n i s 0.1,$ $f i n d$ $a) t h e w o r k d o n e b y t h e m a n o n t h e$ $b o x$ $b) w o r k d o n e a g a i n s t f r i c t i o n$
	Answered by tanmay.chaudhury50@gmail.com last updated on 10/May/18

	$w o r k d o n e b y t h e m a n i s$ $(m g s i n θ + μ m g c o s θ) \times s$ $= (40 \times 9.8 \times s i n 15^{o} + 0.1 \times 40 \times 9.8 \times c o s 15^{o}) \times 20$ $b) w o r k d o n e a g a i n s t f r i c t i o n$ $= μ m g c o s θ \times s$
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