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Question Number 34803 by Tinkutara last updated on 11/May/18

Commented by ajfour last updated on 11/May/18

Commented by ajfour last updated on 11/May/18

$$2x+y=0$$

Answered by MJS last updated on 11/May/18

$$y=\frac{1}{x}$$$$y=2x+d$$$$2x+d=\frac{1}{x}$$$$x^2+\frac{d}{2}x-\frac{1}{2}=0$$$$x_1=-\frac{d}{4}-\frac{\sqrt{d^2+4}}{4};y_1=\frac{d}{2}-\frac{\sqrt{d^2+4}}{2}$$$$x_2=-\frac{d}{4}+\frac{\sqrt{d^2+4}}{4};y_2=\frac{d}{2}+\frac{\sqrt{d^2+4}}{2}$$$$M=\left(\begin{array}{c}\frac{x_1+x_2}{2}\\ \frac{y_1+y_2}{2}\end{array}\right)=\left(\begin{array}{c}-\frac{d}{4}\\ \frac{d}{2}\end{array}\right)$$

Commented by Tinkutara last updated on 12/May/18

Thank you very much Sir! I got the answer. ��������

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