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Question Number 34888 by arnabmaiti550@gmail.com last updated on 12/May/18

Commented by arnabmaiti550@gmail.com last updated on 12/May/18

$$\mathrm{please}\mathrm{help}$$

Answered by tanmay.chaudhury50@gmail.com last updated on 13/May/18

$$Lorentzforce=q\left(\mathit{V}\times \mathit{B}\right)$$$$=qVBsin{90}^o$$$$qVBso{mv}^2/R=qvB$$$$mv=qBR$$$$wR=qBR/m$$$$w=\frac{qB}{m}$$$$\frac{2\mathrm{\Pi }}{T}=\frac{qB}{m}$$$$T=\frac{2\mathrm{\Pi }m}{qB}$$$$$$

Commented by tanmay.chaudhury50@gmail.com last updated on 13/May/18

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