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Question Number 34954 by ajfour last updated on 13/May/18

Commented by ajfour last updated on 13/May/18

$F i n d r e s i s t a n c e o f a c y l i n d r i c a l$ $c o n d u c t o r o f r a d i u s b a n d t h i c k n e s s$ $t w i t h a c o n c e n t r i c h o l e o f r a d i u s$ $a, a c r o s s i t s i n n e r a n d o u t e r$ $s u r f a c e s . (c o n d u c t i v i t y g i v e n σ) .$
	Answered by tanmay.chaudhury50@gmail.com last updated on 13/May/18

	$d R = \frac{1}{σ} \times \frac{d l}{d A} l e t c o n s i d e r e l e m e n t a r y s h e l l$ $t h i c k n e s s d x, c r o s s a r e a 2 Π x \times t s o d l = d x$ $d A = 2 Π x t$ $= \frac{1}{σ} \times \frac{d x}{2 Π x t}$ $R = \frac{1}{2 Π σ t} \int_{a}^{b} \frac{d x}{x}$ $= \frac{1}{2 Π σ t} \times l n (\frac{b}{a})$
	Commented by ajfour last updated on 13/May/18

	$c o r r e c t a n s w e r .$ $b u t d A s h o u l d b e A a n d n o t d A .$
	Commented by tanmay.chaudhury50@gmail.com last updated on 14/May/18

	$t r u e . . . t h a n k s . .$
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