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Question Number 34980 by NECx last updated on 14/May/18

If cos45° =(1/(√2)) . Find cos45.1°

Ifcos45°=12.Findcos45.1°

Answered by ajfour last updated on 14/May/18

cos ((π/4)+(π/(1800)))≈cos ((π/4))−(π/(1800))sin (π/4)      =(1/(√2))(1−(π/(1800))) =0.707(1−((0.0314)/(18)))     =0.707(1−0.00173)     ≈ 0.707−0.0012 ≈ 0.7058 .

cos(π4+π1800)cos(π4)π1800sinπ4=12(1π1800)=0.707(10.031418)=0.707(10.00173)0.7070.00120.7058.

Answered by tanmay.chaudhury50@gmail.com last updated on 14/May/18

y=cosx  y+△y=cos(x+△x) here x=45^(o )  x+△x=45.1^o   △y=cos(x+△x)−cosx     ((△y)/(△x))=(dy/dx)  △y=(dy/dx).△x  △y=−sinx×(Π/(1800))  △y=−((1/(√2)))×(Π/(1800))  so  cos(45.1^o )=(1/(√2))−(1/(√2))×(Π/(1800))  cos(45.1)^o =(1/(√2))(1−(Π/(1800)))  cos(45.1)^o =((√2)/2)×(1−0.0017453293)  cos(45.1)^o =0.7071067812×0.9982546707  cos(45.1)^o =0.705872647  180^o =Π radian  1^o =(Π/(180 ))   so  (0.1)^o =(Π/(1800))

y=cosxy+y=cos(x+x)herex=45ox+x=45.1oy=cos(x+x)cosxyx=dydxy=dydx.xy=sinx×Π1800y=(12)×Π1800socos(45.1o)=1212×Π1800cos(45.1)o=12(1Π1800)cos(45.1)o=22×(10.0017453293)cos(45.1)o=0.7071067812×0.9982546707cos(45.1)o=0.705872647180o=Πradian1o=Π180so(0.1)o=Π1800

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