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Question Number 35244 by JOHNMASANJA last updated on 17/May/18
ify=sin−1x1−x2showthat(1−x2)dydx−xy=1
Commented by math1967 last updated on 17/May/18
(1−x2)y=sin−1x(1−x2)dydx−2xy=11−x2(1−x2)32dydx−2xy=1Butnot(1−x2)dydx−2xy=1?????????????
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