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Question Number 35246 by JOHNMASANJA last updated on 17/May/18
ifxp+yq=(x+y)p+qprovethatdydx=yx
Commented by math1967 last updated on 17/May/18
plz.checkquestionxp+yqORxp.yq?????????????????
Answered by tanmay.chaudhury50@gmail.com last updated on 18/May/18
dyy−dxx=0∫dyy=∫dxxlny=lnx+lnkln(yx)=lnky=xknowputy=xkinthegivenexpressionLHSxp+yqxp+xqkqRHS(x+y)p+q(x+xk)p+axp+q×(1+k)p+qsoLHSnotequalstoRHSsoquestioniswrongithink....
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