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Question Number 35427 by abdo.msup.com last updated on 18/May/18
calculate∫25ex+1x+1dx
Commented by prof Abdo imad last updated on 19/May/18
changementx+1=tgivex=t2−1I=∫36ett2tdt=2∫36etdt=2{e6−e3}.
Answered by ajfour last updated on 19/May/18
I=2∫36etdt=2(e6−e3).
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