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Question Number 35476 by NECx last updated on 19/May/18

In a match between A and B.The  probability of A winning is (4/(11)),  the probabilith of B winning is (2/(11)).  What is the probability if they  were to draw the match?

$${In}\:{a}\:{match}\:{between}\:{A}\:{and}\:{B}.{The} \\ $$$${probability}\:{of}\:{A}\:{winning}\:{is}\:\frac{\mathrm{4}}{\mathrm{11}}, \\ $$$${the}\:{probabilith}\:{of}\:{B}\:{winning}\:{is}\:\frac{\mathrm{2}}{\mathrm{11}}. \\ $$$${What}\:{is}\:{the}\:{probability}\:{if}\:{they} \\ $$$${were}\:{to}\:{draw}\:{the}\:{match}? \\ $$

Commented by Rasheed.Sindhi last updated on 19/May/18

 Probability to draw the match:      1−((4/(11))+(2/(11)))=(5/(11))

$$\:{Probability}\:{to}\:{draw}\:{the}\:{match}: \\ $$$$\:\:\:\:\mathrm{1}−\left(\frac{\mathrm{4}}{\mathrm{11}}+\frac{\mathrm{2}}{\mathrm{11}}\right)=\frac{\mathrm{5}}{\mathrm{11}} \\ $$

Commented by NECx last updated on 20/May/18

why did you add up the 2 probabilities

$${why}\:{did}\:{you}\:{add}\:{up}\:{the}\:\mathrm{2}\:{probabilities} \\ $$

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