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Question Number 35533 by jonesme last updated on 20/May/18

$$\mathrm{If}\mathrm{the}\mathrm{roots}\mathrm{of}\mathrm{the}\mathrm{equation}{x}^2-px+q=0$$$$\mathrm{differ}\mathrm{by}\mathrm{unity},\mathrm{then}$$

Answered by ajfour last updated on 20/May/18

$${(\alpha -\beta )}^2=p^2-4q=1$$$$or{p}^2-4q-1=0.$$

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