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Question Number 35594 by Rio Mike last updated on 20/May/18
Giventhat18,24,andk+14arethreeconsecutivetermsofanarithmeticprogressionFinda)thecommondifferenceb)thevalueofkc)thefirsttermifthe4thtermis12.d)thesumofthefirsttwelvetermsoftheprogression.
Answered by tanmay.chaudhury50@gmail.com last updated on 20/May/18
a)c.d=6b)k+14=30k=16c)a+(4−1)×6=12a=−6d)s=122{2×−6+(12−1)×6}=6(−12+66)=6×54=324
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