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Question Number 35738 by Rio Mike last updated on 22/May/18

$$Giventhat{\int }_0^k{x}^2=16$$$$findthevalueofk$$

Answered by tanmay.chaudhury50@gmail.com last updated on 22/May/18

$${\int }_0^k{x}^{2}dx=16$$$$\mid \frac{x^3}{3}{\mid }_0^k=16$$$$\frac{k^3}{3}=16$$$$k=2\times {\left(6\right)}^{\frac{1}{3}}$$$$$$

Answered by candre last updated on 22/May/18

$$\underset{0}{\stackrel{k}{\int }}{x}^{2}dx=16$$$$\frac{k^3}{3}=16$$$$k^3=16\times 3=2^4\cdot 3=48$$$$k=\sqrt[3]{48}=2\sqrt[3]{6}$$

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