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Question Number 36049 by Rio Mike last updated on 27/May/18

A triangle △ABC is constructed   such that ∠B= 90°  and AB= 5cm  Given that ∠C= 45° . show that   the point (2,0) lie on the line   BC and is perpendicular to AB but  meet at 45^ ° with the line AC.

$$\mathrm{A}\:\mathrm{triangle}\:\bigtriangleup\mathrm{ABC}\:\mathrm{is}\:\mathrm{constructed}\: \\ $$$$\mathrm{such}\:\mathrm{that}\:\angle\mathrm{B}=\:\mathrm{90}°\:\:\mathrm{and}\:\mathrm{AB}=\:\mathrm{5cm} \\ $$$$\mathrm{Given}\:\mathrm{that}\:\angle\mathrm{C}=\:\mathrm{45}°\:.\:\mathrm{show}\:\mathrm{that} \\ $$$$\:\mathrm{the}\:\mathrm{point}\:\left(\mathrm{2},\mathrm{0}\right)\:\mathrm{lie}\:\mathrm{on}\:\mathrm{the}\:\mathrm{line}\: \\ $$$$\mathrm{BC}\:\mathrm{and}\:\mathrm{is}\:\mathrm{perpendicular}\:\mathrm{to}\:\mathrm{AB}\:\mathrm{but} \\ $$$$\mathrm{meet}\:\mathrm{at}\:\mathrm{45}^{} °\:\mathrm{with}\:\mathrm{the}\:\mathrm{line}\:\mathrm{AC}. \\ $$$$ \\ $$

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