Question Number 36059 by solihin last updated on 28/May/18
Answered by Rasheed.Sindhi last updated on 28/May/18
$$\frac{\mathrm{z}_{\mathrm{1}} +\mathrm{z}_{\mathrm{2}} }{\mathrm{z}_{\mathrm{3}} }=\frac{\left(\mathrm{1}+\mathrm{2i}\right)+\left(\mathrm{4}−\mathrm{3i}\right)}{−\mathrm{5}−\mathrm{2i}} \\ $$$$=\frac{\mathrm{5}−\mathrm{i}}{−\mathrm{5}−\mathrm{2i}}×\frac{−\mathrm{5}+\mathrm{2i}}{−\mathrm{5}+\mathrm{2i}}=\frac{−\mathrm{25}+\mathrm{10i}+\mathrm{5i}+\mathrm{2}}{\left(−\mathrm{5}\right)^{\mathrm{2}} −\left(\mathrm{2i}\right)^{\mathrm{2}} } \\ $$$$\frac{−\mathrm{23}}{\mathrm{29}}+\frac{\mathrm{15}}{\mathrm{29}}\mathrm{i} \\ $$