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Question Number 36059 by solihin last updated on 28/May/18

Answered by Rasheed.Sindhi last updated on 28/May/18

$$\frac{{\mathrm{z}}_1+{\mathrm{z}}_2}{{\mathrm{z}}_3}=\frac{(1+2\mathrm{i})+(4-3\mathrm{i})}{-5-2\mathrm{i}}$$$$=\frac{5-\mathrm{i}}{-5-2\mathrm{i}}\times \frac{-5+2\mathrm{i}}{-5+2\mathrm{i}}=\frac{-25+10\mathrm{i}+5\mathrm{i}+2}{{(-5)}^2-{\left(2\mathrm{i}\right)}^2}$$$$\frac{-23}{29}+\frac{15}{29}\mathrm{i}$$

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