i want to know how α^2 + β^2 = (α+β)^2 − 2αβ why not α^2 +β^2 = (α+β)^2 + 2αβ?


Question and Answers Forum

All Questions Topic List
Others Questions
Previous in All Question Next in All Question
Previous in Others Next in Others
Question Number 36080 by Rio Mike last updated on 28/May/18

$i want to know how$ $α^{2} + β^{2} = {(α + β)}^{2} - 2 α β why not$ $α^{2} + β^{2} = {(α + β)}^{2} + 2 α β ?$
Commented by Joel579 last updated on 29/May/18

$α^{2} + β^{2} = {(α + β)}^{2} - 2 α β$ $= {(α - β)}^{2} + 2 α β$
	Answered by tanmay.chaudhury50@gmail.com last updated on 28/May/18

	$v a l u e o f {(α + β)}^{2} - 2 α β$ $= α^{2} + 2 α β + β^{2} - 2 α β$ $= α^{2} + β^{2}$ $v a l u e o f {(α + β)}^{2} + 2 α β$ $= α^{2} + 2 α β + β^{2} + 2 α β$ $= α^{2} + β^{2} + 4 α β$ $t h a t i s w h y . . .$
	Answered by Rasheed.Sindhi last updated on 28/May/18

	$α^{2} + β^{2}$ $= α^{2} + 2 α β + β^{2} - 2 α β$ $= {(α + β)}^{2} - 2 α β$
Terms of Service
Privacy Policy
Contact: info@tinkutara.com

Question and Answers Forum